Show the homolysis reaction of benzoyl peroxide,$(C_6H_5CO)_2O_2$.
The homolysis of benzoyl peroxide $(C_6H_5CO)_2O_2$ involves the cleavage of the $O-O$ bond to form two benzoyloxy radicals,which subsequently undergo decarboxylation to form phenyl radicals and carbon dioxide:
$(C_6H_5CO)_2O_2$ $\xrightarrow{\text{Homolysis}} 2 C_6H_5COO\bullet$ $\rightarrow 2 C_6H_5\bullet + 2 CO_2$
$(C_6H_5CO)_2O_2$ $\xrightarrow{\text{Homolysis}} 2 C_6H_5COO\bullet$ $\rightarrow 2 C_6H_5\bullet + 2 CO_2$
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Similar Questions
Which carbocation is the least stable?
Easy
View SolutionThe stability of the following carbanions is in the order of:
Medium
View SolutionState True or False for the following statements:
$(i)$ Only carbocation is formed by homolytic cleavage of a bond.
$(ii)$ By heterolytic cleavage of a bond,a carbocation or carbanion is formed.
$(iii)$ The carbon of a carbanion is $sp^2$ and the carbon of a carbocation is $sp^3$.
$(iv)$ The carbon of a carbanion is $sp^3$ and the carbon of a carbocation is $sp^2$.
$(i)$ Only carbocation is formed by homolytic cleavage of a bond.
$(ii)$ By heterolytic cleavage of a bond,a carbocation or carbanion is formed.
$(iii)$ The carbon of a carbanion is $sp^2$ and the carbon of a carbocation is $sp^3$.
$(iv)$ The carbon of a carbanion is $sp^3$ and the carbon of a carbocation is $sp^2$.
Medium
View SolutionArrange the following carbocations in the decreasing order of their stability:
$a$. $CH_3-CH^{+}-CH_3$
$b$. $CH_3-CH^{+}-OCH_3$
$c$. $CH_3-CH^{+}-COCH_3$
$a$. $CH_3-CH^{+}-CH_3$
$b$. $CH_3-CH^{+}-OCH_3$
$c$. $CH_3-CH^{+}-COCH_3$
Difficult
View SolutionThe stability order of the following carbocations is:
Medium
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